User blog:Helloglitcher666/Divisors of the 10 composite numbers

$$15$$ = 2 × 3^2

$$39$$ = 2^4 × 3

$$48$$ = 2^2 × 3 × 5

$$93$$ = 2^3 × 3 × 5

$$264$$ = 2^2 × 3 × 5 × 7

$$132$$ = 2 × 3 × 5 × 7

$$2145$$ = 2^2 × 3 × 5 × 7 × B

$$21450$$ = 2^2 × 3 × 5 × 7 × B × 10

$$428X0$$ = 2^3 × 3 × 5 × 7 × B × 10

$$1171X5J47J$$ = 2^4 × 3^2 × 5^2 × 7 × B × 10 × 14 × 16 × 1X

$$3360515712$$= 3 × 7 × 47 × 142 × 18X × 281

$$68282404264$$ = 2^3 × 38 × 76 × 465 × 2041

$$718B544260$$ = 2^8 × 3 × 5 × 10 × 16 × 61 × 5J8